Arestaurant chain sells 200,000 burritos each day when it charges $6.00 per burrito. for each $0.50 increase in price, the restaurant chain sells 10,000 less burritos. a. how much should the restaurant chain charge to maximize daily revenue? the restaurant chain should charge $ per burrito. b. what is the maximum daily revenue? b. the maximum daily revenue is $.

1280000

Step-by-step explanation:

Given that a restaurant chain sells 200,000 burritos each day when it charges $6.00 per burrito.

For each $0.50 increase in price, the restaurant chain sells 10,000 less burritos.

If x is the number of times price increased then sales would be

Revenue after price change

Now we can use calculus to find maximum

Let R(x) =

Equate first derivative to 0

we get x = 4

So maximum revenue is when 4 times price increased.

New price =

Sales =

Max revenue = .

the last choice

step-by-step explanation:

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: