What is cot θ when sin θ = square root of 3 divided by 3? rationalize the denominator if necessary.

cotΘ = -

Step-by-step explanation:

Using the trigonometric identities

cot x =

sin²x + cos²x = 1 ⇒ cosx = ±

Since Θ is in second quadrant then cosΘ < 0

cosΘ = - )^2

        = - = - = -

Hence

cotΘ =

        = - ×

        = - = -

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.