Trained dolphins are capable of a vertical leap of 7.0 m straight up from the surface of the water-an impressive feat. suppose you could train a dolphin to launch itself out of the water at this same speed but at an angle.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

step-by-step explanation:

4  

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5r

54

5856

542

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86

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565

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55898

786

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5896

8656265

556478

v=1788.75

step-by-step explanation:

i belive that is the answer