An adult can lose or gain two pounds of water in the course of a day. assume that the changes in water weight are uniformly distributed between minus two and plus two pounds in a day. what is the standard deviation of your weight over a day?

1.15 pounds

Step-by-step explanation:

For uniform distribution.

The standard deviation is  :

, where a = Lower limit of interval [a,b].

b = Upper limit of interval [a,b].

Given : The changes in water weight are uniformly distributed between minus two and plus two pounds in a day.

i.e. Interval =  [-2 , +2]

Here , a= -2 and b= 2

Then, the standard deviation is  :

Hence, the standard deviation of your weight over a day =  1.15 pounds

47 - 90 = 43

43 - 180 = x

x = 137