What is the maximum value of the feasible regions if p = 120x + 100y
region 1 (0 ,5)
region 2 ( 0, 4)
region 3 (4,0)
region 4 (3,0)

The maximum value of the feasible regions is P=500

Step-by-step explanation:

we know that

To find out the maximum value of the feasible regions, substitute the value of x and the value of y of each region in the objective function P and then compare the results

we have

Region 1 (0,5)

For x=0, y=5

substitute

Region 2 (0,4)

For x=0, y=4

substitute

Region 3 (4,0)

For x=4, y=0

substitute

Region 4 (3,0)

For x=3, y=0

substitute

Compare

The maximum value of the feasible regions is P=500

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for