Arectangular field is 40 feet longer than it is wide. it takes a total of 200 feet of fencing to enclose it. what are the dimensions of the field?

Length 70 ft

Width 30 ft

Step-by-step explanation:

Let L be the length and W the width.

The rectangular field is 40 feet longer than it is wide:

L = W + 40

It takes a total of 200 feet of fencing to enclose it (to surround its perimeter)

L+L+W+W = 200 > 2L+2W = 200

Replace the L from the first equation

2(W+40) + 2W = 200 > 2W+80+2W = 200 >

> 4W = 200 -80 > 4W = 120 > W= 120/4 = 30

Now, use the value of W to find L  

L = W + 40 > L = 30 + 40 = 70

and the dimensions are: length L = 70 ft and width W = 30 ft

i think the answer is fried chicken ; >

step-by-step explanation:

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.