Find the area of the surface. the surface with parametric equations x = u2, y = uv, z = 1 2 v2, 0 ≤ u ≤ 2, 0 ≤ v ≤ 2.

du dv

Step-by-step explanation:

let, r = x i + y j + z k , where i, j, k are unit vectors.

r = i + uv j + 12 k

we know that the surface area of a surface represented by r(u,v) is

=

here,

      = 2u i + v j

      = u j + 24 v k

      Cross product =

                              = 24 i - 48 uv j + 2 k

The modulus of the cross product is

so, the surface area is

            du dv

and the answer has to be left as the integral itself as the integral of square root of biquadratic can not be calculated(with random co efficients).

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula