Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29

a. about 54.6 units and 39.4 units

c. about 46.8 units n 64.6 units

b. about 63.9 units and 41.0 units

d. about 67.5 units and 36.8 units select the best answer from the choices provided

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒

⇒

Using value of sin 29°

⇒

Cross multiplying both side.

⇒ Sin B=

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

⇒

Using the value of sine and cross multiplying both side.

⇒ C=

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle=

∴ Perimeter of triangle= 63.9 units

a. 19,958,400

step-by-step explanation:

hope this

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted