The shape of the distribution of the time required to get an oil change at a 15 minute facility is unknown. however, records indicate that the mean time is 16.1 minutes and the standard deviation is 4.6 minutes.
a) to compute the probabilities regarding the sample mean using the normal model, what size sample would be required?
b) what is the probability that a random sample of n = 40 oil changes results in a sample mean time of less than 15 minutes?
a) choose the required sample size:
1. the normal model cannot be used if the shape is unknown
2. sample size need to be greater than 30
3. sample size needs to be less than 30
4. any sample size could be used.
b) the probability is approximately? (round to 4 decimal places as needed)

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.