Plz prove this triangle congruence.

ΔDBE≅ΔQAP  (by RHS criteria)

Step-by-step explanation:

Given that, , , ⊥

and ⊥

⇒∠PAQ=90° and ∠EBD=90°(definition of perpendicular lines)

Its given that PB=AE,

subtracting AB on both sides,

we get: PB-AE=AB-AE

         ⇒PA=EB (equals subtracted from equals, the remainders are equals)

Therefore, ΔDBE≅ΔQAP (by RHS criteria)

conditions for congruence:

So, ∡D=∡Q(as congruent parts of congruent triangles are equal)