Another student was upset for a diferent reason. he thought that test 2 was too long and said reason. he thought that test 2 was too long and said, "at least half of the significance level of o.01, test the student's claim that at least half of the students were still taking the (18 pts) class was stll testing when there were only 10 minutes left! " (students are allowed 90 minutes to complete the test at the 80-minute mark. one of the mat 110 instructors thought that test 2 was easier than test 1. she said, "i think students scored a lot higher on the second test." can you conclude at a o.05 level of significance that the scores for test 2 were higher than for test 1? (18 pts) united states

it would to have a graph or something ! but i had this question so its false

step-by-step explanation:

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step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: