An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standard deviationσ=.1 mg. suppose that the results of fivesuccessive weightings of the same object are as follows: 3.142, 3.163, 3.155, 3.150, 3.141.(a) determine a 95 percent confidence interval estimate of the true weight.
(b) determine a 99 percent confidence interval estimate of the true weight.

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

And margin of error (ME) can be calculated using the formula

ME= where

Using the numbers 95% confidence interval estimate of the true weight is:

3.150±≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150±≈3.150±0.206

y + 11 = (1/4)(x + 16)

step-by-step explanation:

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y