Let c(n) be the constant term in the expansion of (x + 4)n. prove by induction that c(n) = 4n for all n is in n. (induction on n.) the constant term of (x + 4)1 is = 4 . suppose as inductive hypothesis that the constant term of (x + 4)k − 1 is for some k > 1. then (x + 4)k = (x + 4)k − 1 · , so its constant term is · 4 = , as required.

C(n) = 4 n for all possible integers n in N. This statement is true when n=1 and proving that the statement is true for n=k when given that statement is true for n= k-1

Step-by-step explanation:

Lets P (n) be the statement  

C (n) = 4 n

if n =1

(x+4)n = (x+4)(1)=x+4

As we note that constant term is 4  C(n) = 4

    4 n= 4 (1) =4

P(1) is true as C(n) = 4 n

when n=1

Let P (k-1)

    C(k-1)=4(k-1)

we need to proof that p(k) is true

C(k) = C(k-1) +1)

      =C(k-1)+C(1)           x+4)n is linear

      =4(k-1)+ C(1)          P(k-1) is true

       =4 k-4 +4              f(1)=4

        =4 k

So p(k) is true

By the principle of mathematical induction, p(n) is true for all positive integers n

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

look a the sides they are perpendicular