Which inequality has a solution set of {x| x> 3or x< -3}?

x>3

Step-by-step explanation:

I believe you are asking which is representative of |x| so here is the example of that.

x²-3²<0

Step-by-step explanation:

taking it from x>3 or x<-3

there fore x-3>0 or x+3<0

so the smaller one sign is changed

x-3<0 orx+3<0

so (x-3)(x+3)<0

expanding x²-3²<0

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

i would need to see the dot plot : )