The front walkway from the street to pam's house has an area of 250ft^2. its length is two less than four times its width. find the length and width of the walkway. round to the nearest tenth of a foot.

the length of the walkway is 30.64ft

The width of the walkway is 8.16ft

Step-by-step explanation:

Since the walkway has length and width, it is rectangular in shape. For a rectangle, the two lengths and two widths are equal. The area is expressed as length, L × Width,W.

The front walkway from the street to Pam's house has an area of 250ft^2. It means that

LW = 250

Its length is two less than four times its width. It means

L = 4W - 2

Substituting L = 4W - 2 into LW = 250, it becomes

W(4W - 2) = 250

4W^2 - 2W- 250 = 0

Using the general formula for quadratic equations,

W = [- b ± √b^2 - 4ac]/2a

a = 4

b = -2

c = - 250

W= [- - 2 ±√-2^2 -4(4 × -250)]/2×4

= (2 ± √4 + 4000)/8

= (2 ±63.277)/8

W= (2 + 63.277)/8 or W = (2 - 63.277)/8

W = 8.16 or W = - 7.91

Since the width cannot be negative, width = 8.16 ft

LW = 250

8.16L = 250

L = 250/8.16 = 30.64 ft

c.35

step-by-step explanation:

8+13=21

21+8=29

29+6=35