Suppose a ball is thrown directly upward from a height of 7 feet with an initial velocity of 50 feet per second. use the quadratic formula or a graphing calculator to find the number of seconds it takes the ball to hit the ground. round the nearest tenth of a second.

t = 3.3 seconds

Step-by-step explanation:

From the formula of vertical motion of an object under gravity we can write the equation

....... (1)

Where u is the initial velocity (in feet per second) of throw of the object and t is time of travel in seconds and the value of g i.e. gravitational acceleration is 32 feet/sec².

Now, while a ball is thrown vertically upward with velocity 50 ft/sec from a height of 7 ft then the time of travel of the ball before reaching the ground, the equation (1) will be written as

As we have selected the upward direction as positive so, gravitational acceleration,g will be negative and as the displacement is downward by 7 feet, so it will be negative.

⇒ 16t² - 50t - 7 = 0 ........ (2)

Now, applying Sridhar Acharya formula,

{Neglecting the negative root as t can not be negative}

⇒ t = 3.3 seconds {Rounded to the nearest tenth}

(Answer)

32

step-by-step explanation: