Apoll found that 64% of a random sample of 1076 adults said they believe in ghosts.

question 1. find the margin of error -/n), abbreviated me, for this poll if we want 90% confidence in our estimate of the proportion of adults who believe in ghosts.
me=

(round to 3 decimal places.)

question 2. find the margin of error needed to be 99% confident.
me= (round to 3 decimal places.)

Margin of error at 90% is 0.024

Margin of error at 99% is 0.037

Step-by-step explanation:

Sample size = 1076

A poll found that 64% of a random sample of 1076 adults said they believe in ghosts.

So, No. of adults said they believe ghosts =

So, x = 688

n = 1076

z at 90% confidence is 1.64

So, margin of error at 90% is 0.024

Find the margin of error needed to be 99% confident.

z at 99% confidence is 2.58

So, margin of error at 99% is 0.037

it's both, now can you answer my most recent question?

4th option is correct xy=-10

if this was to u plzz mark me the brainliest