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Mathematics, 26.11.2019 07:31 sxbenn

(1 point) for the series ∑[infinity]n=11n2+n, the nth term is an= 1/2 which behaves like bn= 1/2 for large n. then an/bn= 1/4 and limn→[infinity]an/bn=c where c= obeys 0

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(1 point) for the series ∑[infinity]n=11n2+n, the nth term is an= 1/2 which behaves like bn= 1/2 for...
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