The path of a soccer ball after it is
kicked from a height of 0.5 m above
the ground is given by the equation
h = -0.1d^2+ d + 0.5, where h is the
height, in wetres, above the ground and
d is the horizontal distance, in metres.
a) how far has the soccer ball travelled
horizontally, to the nearest tenth of a
metre, when it lands on the ground?

step-by-step explanation:

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.