The monthly starting salaries of students who receive an mba degree have a population standard deviation of $120. what sample size should be selected to obtain a .95 probability of estimating the population mean monthly income within a margin of $20? [sample size]

138

Step-by-step explanation:

Population standard deviation =

.95 probability of estimating the population mean monthly income within a margin of $20

So, Significance level = 1-0.95 = 0.05

α =0.05

Margin error = 20

Z at 0.05 = 1.96

So, n = 138

Hence sample size should be 138 selected to obtain a .95 probability of estimating the population mean monthly income within a margin of $20

i dont know sorry

step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17