Km
two buses leave a station at the same time and travel in opposite directions. one bus travels 10 - - slower than the other. if the two buses are 1442
kilometers apart after 7 hours, what is the rate of each bus?
rate of the slower bus:
x
5
?
rate of the faster bus:

The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph  .

Step-by-step explanation:

Given as :

The two buses apart 1442 km

The time taken for apart = 7 hours

Let The speed of faster bus = x kmph

The speed of slower bus = ( x - 10 ) kmph

Now Speed =

∵ Both the buses traveling in opposite direction

So, The speed of faster bus + the speed of slower bus =  

Or, x + x - 10 =

or, 2 x = 206 + 10

or, 2 x = 216

∴  x =

I.e x = 108  kmph

So, The speed of faster bus = x = 108 kmph

And The speed of slower bus = ( x - 10 ) = 108 - 10 = 98 kmph

Hence The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph  . Answer

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places