Mike, paul, and charlie went fishing. everyone caught salmon and pike. mike caught 1 pike and 4 salmon; charlie caught 5 pike and 2 salmon. paul caught half the number of pike that both charlie and mike caught combined, and 1 less salmon than charlie caught. how many of each kind of fish did paul catch? what was the total number of fish the three boys caught?

Paul caught 3 pike and 1 salmon

The total number of fish the three boys caught is 16

Solution:

According to question,

Mike caught 1 pike and 4 salmon

Charlie caught 5 pike and 2 salmon

Paul caught half the number of pike that both Charlie and Mike caught combined, and 1 less salmon than Charlie caught

Pike caught by Paul = half of number of pike that both charlie and mike caught combined =

Salmon caught by Paul = 1 less salmon than Charlie caught = 2 - 1 = 1

Thus, Paul caught 3 pike and 1 salmon

Total of numbers Pike caught by three boys are  

5 + 1 + 3 = 9 pikes

Total of numbers salmon caught by three boys are  

4 + 2 + 1 = 7 salmons

Hence , the total number of fish caught are

9 + 7 = 16 fishes  

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.