The digits of a two-digit number sum to 8. when the digits are reversed the resulting number is 18 less than the onginal
number. what is the original number?

53

Step-by-step explanation:

Given: The sum of two digit number is 8

           Reversing the digit will get us number 18 less than the original.

Lets take x as tenth digit of our number and y as unit digit of our number.

As given sum of digit is 8

∴

∴ -       equation 1

We also know that reversing the digit will get us number 18 less than the original.

∴

Now, lets put the value of y from equation 1

⇒

⇒

⇒

∴

Next, substituting the value of x in equation 1

⇒

∴

∴ The original number is 53, sum of the digit is 8 and if we reverse the digit of the number, we get 35, which is 18 less than the original number.

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.