Take the laplace transform of the following initial value problem and solve for y(s)=l{y(t)}: y′′−2y′−24y=s(t)y(0)=0,y′(0)=0where s is a periodic function defined bys(t)={1,0,0≤t< 11≤t< 2, and s(t+2)=s(t) for all t≥0.hint: : use the formula for the laplace transform of a periodic function.

im sorry but no. i just need to answer for 50 poonts oof

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube