Acollege is currently accepting students that are both in-state and out-of-state. they plan to accept three times as many in-state students as out-of-state, and they only have space to accept 100 out-of-state students. let x = the number of out-of-state students and y = the number in-state students. write the constraints to represent the incoming students at the college.

\[y < = 300\]

Step-by-step explanation:

Let x = number of out-of-state students at the college

Let y = number of in-state students at the college

As per the given problem, the constraints are as follows:

\[x < = 100\]     (1)

\[y = 3 * x\]       (2)

From the given equations (2), \[ x = y/3 \]

Substituting in (1):

\[y/3 < = 100\]

Or, \[y < = 300\] which is the constraint representing the incoming students.

Constraint that represents the incoming students at the college is

y ≤ 300

Step-by-step explanation:

It is given in this question that a college is currently accepting both in-state and out of state students where,

y = Number of in-state students

x = Number of out-of-state students

Their plan is to accept three times as many in students as out of state

Which is represented by he equation y = 3x

x =

College has space for 100 out-of-state students only, so the inequality which represents this situation will be

x ≤ 100

Now the constraint to represent the incoming students in the college will be

y ≤ 300

Therefore, constraint that represents the incoming students at the college is y ≤ 300

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hope it's you

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.