Abcd is a trapezoid with mid-segment (e f). if ad=5x-11, e f=3x+7, bc=2x+7, how many units in length is (e f) i need equation, algebra procedures, value of x, and length of (e f)

x = 18

Step-by-step explanation:

The length of the midsection is the sum of the two bases divided by 2. Remember that the bases of a trapezoid are the two parallel sides. So that means:

((5x - 11) + (2x + 7)) /2 = 3x + 7

Simplify ((5x - 11) + (2x + 7)) /2:

(5x - 11) + (2x + 7) /2 = (5x + 2x - 11 + 7) /2 = (7x - 4) /2

Therefore:

(7x - 4) /2 = 3x + 7

Now solve this simultaneous equation:

7x - 4 = 6x + 14

7x = 6x + 18

x = 18

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

she will travel a distance in the range of 3 - 11 miles