Select the function that matches the graph.
y = 3x
y = 3x2 + 1
y = 3x - 1
y = 3x + 1

The graph is missing, but we can draw and describe each option.

This is a linear function which passes throuhg the origin of the coordinate system because it doesn't have the constant which is the y-intercept of the line.

The first image attached shows this function.

This is a quadratic function. Its graph belongs to a parabola, all quadratic functions are represented by a parabola. In this case, the parabola has a vertex at (0,1). The second image attached shows this function.

This is also a linear function, which is parallel to the first function, because they have the same slope of 3. But this one has y-intercept at (0,-1). The third image attached shows this function.

This is also a linear function parallel to function 1 and function 3. The fourth image attached shows its graph. In this case, the line has y-intercept at (0,1).

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐