Bryce tried to solve an equation step by step.
\qquad\begin{aligned} \dfrac83& =3\left(c+\dfrac53\right) \\ \dfrac83& =3c+\dfrac53& \green{\text{step } 1} \\ 1& =3c& \blue{\text{step } 2} \\ \dfrac13& =c& \purple{\text{step } 3} \end{aligned}
3
8


3
8


1
3
1




=3(c+
3
5

)
=3c+
3
5


=3c
=c


step 1
step 2
step 3