Ataxi charges a base fee plus $0.75/km.
a 10-km trip costs $8.70.
a) what is the rate of change in this situation?
b) write an equation for the cost of hiring a taxi in terms of length of the trip.
c) what does initial value represent in this situation.

a)  $0.75/Km

b)

c) The fixed base charge

Step-by-step explanation:

We know the taxi charges $0.75 per km and we are told a 10-Km trip costs $8.70. We can clearly see there is a base charge and a variable charge

a) The rate of change tells us the variation of the charges with the distance of the trip. In this case, the rate of change is $0.75/Km

b) If x is the length of the trip in Km, the equation of the total fare F(x) is

We know a 10-Km trip costs $8.70. Replacing those values would give us the value of A

8.70=A+0.75(10)

8.70=A+7.5

Using the value of A we have

c) The initial value represents the charge a customer has to pay even if they don't travel any distance, i.e. the fixed base charge

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

step-by-step explanation:

when the line is solid:

when the line is dashed:

this > inequality sign means:

this < inequality sign means:

this > inequality sign means:

this < inequality sign means:

about the problem:

srry i'm not done ! i'll