Is x^3+3x an even or odd function and is it symmetric in respect to the y-axis, origin, or neither

+ 3x is an odd function and it is symmetric about the origin.

Step-by-step explanation:

A function is odd if the graph of the function is symmetrical about the origin, or a function is odd if f(-x) = -f(x). To determine if a function is even or odd, you substitute -x for x in the function, if the resulting function is the same as the original function, then the function is even but if otherwise , the function is odd. Considering the graph of + 3x , it is symmetric about the origin , therefore it is an odd function.

Considering the second method of checking , let us substitute -x for x in the equation.

+ 3x

+ 3(-x)

= - 3x , this shows clearly that it is an odd function.

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

b

step-by-step explanation: