Ametallurgist has one alloy containing 34% copper another containing 48% copper. how many pounds of each alloy must he use to make 46 pounds of the third alloy containing 37% copper

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be in pounds and the weight of second alloy used be in pounds.

       Total weight =        

      Total weight of copper =

       Subtracting 34 times first equation from second equation,

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80

idk

step-by-step explanation: