The sum of three integers is 12
12
. the sum of the first and second integers exceeds the third by 32
32
. the third integer is 15
15
less than the first. find the three integers.

First = 5, second = 17, third = -10

Step-by-step explanation:

First integer = x

The third integer is 15 less than the first, so

Third integer = x - 15

The second integer = y

The sum of the first and second integers exceeds the third by 32, so

The sum of the first and second integers = x + y

The third integer = x - 15

x + y is 32 more than x - 15, hence

x + y - 32 = x - 15

y - 32 = -15

y = 32 - 15

y = 17

The second integer = 17

The sum of three integers is 12, so

x + 17 + x - 15 = 12

2x + 2 = 12

2x = 12 - 2

2x = 10

x = 5

x - 15 = 5 - 15 = -10

idk the answer but just put a

step-by-step explanation:

what are you trying to solve here

step-by-step explanation: