(1 point) a cup of coffee at 100 degrees celsius is put into a 30 degree celsius room when t=0. the coffee's temperature, f(t), is changing at a rate given by f′(t)=−7(0.8)t degrees celsius per minute, where t is in minutes.

your question seems incomplete but if you looking to find the resulting equation to solve for temperature at a particular time you can use this 28t^2

Step-by-step explanation:

F'(t) = 7(0.8)t

Integrating the RHS

Temp= integral of f'(t)= 28t^2

Therefore, T(°c)= 28t^2

true

step-by-step explanation:

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