Aparticle whose mass is 4 kg moves in xyplane with a constant speed of 2 m/s in the positive x-direction along y = 6 m. find the magnitude of its angular momentum relative to the point (x0, y0), where x0 = 0.9 m and y0 = 10 m. answer in units of kg m2 /s.

32.8kgm^2/s

Step-by-step explanation:

1. Angular momentum is a product of linear momentum and the distance of the object from a rotation axis.

2. Linear momentum (L) is given as :

L = mv

Where: m= mass = 4kg

v= velocity= 2m/s

=> L = 8kgm/s

Angular momentum (A) = L x centre distance (d) of object from a rotation axis

d = √(0.9-0)^2 + (10-6)^2 = 4.1m

=> A = 8 x 4.1 = 32.8kgm^2/s.

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2