Delaney would like to make a 10 lb nut mixture that is 60% peanuts and 40% almonds. she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds. let p represent the number of pounds of peanuts needed to make the new mixture, and let m represent the number of pounds of the 80% almond-20% peanut mixture.
a) what is the system that models this situation?
b) which of the following is a solution to the system: 4 lb peanuts and 6 lb mixture; 5 lb peanut and 5 lb mixture; 8 lb peanut and 2 lb mixture? show your work.

{a}p + 0.2m = 6

   0.8m = 4

or 5p + m = 30

   m = 5

{b} 5 lb peanuts and 5 lb mixture

Step-by-step explanation:

m1 → desired mixture with composition : 60% peanuts and 40% almonds and weight : 10 lb

⇒weight of peanuts in m1 = 60% × 5 = 6 lb

and weight of almonds in m1 is 4 lb

m2 → mixture with composition : 20% peanuts and 80% almonds and weight : m pounds

⇒weight of peanuts in m2 = 0.2m

and weight of almonds in m2 = 0.8m

p → weight (in pounds) of peanuts added to m2 to make m1

{a}

add p pounds of peanuts to m2 to make m1

equating weights of peanuts and almonds:

p + 0.2m = 6

0.8m = 4

{b}

equation gives m = ⇒ m = 5 lb

Using this in the equation:

p + 1 = 6 ⇒ p = 5 lb

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47