The drama club is selling tickets to their play to raise money for the show's expenses. each student ticket sells for $5 and each adult ticket sells for $9. the auditorium can hold no more than 90 people. the drama club must make a minimum of $610 from ticket sales to cover the show's costs. if 57 student tickets were sold, determine the minimum number of adult tickets that the drama club must sell in order to meet the show's expenses. if there are no possible solutions, submit an empty answer.

  NO SOLUTION

Step-by-step explanation:

The maximum number of adult tickets that can be sold is ...

  90 -57 = 33

The revenue from sale of 57 student and 33 adult tickets is ...

  57×$5 + 33×$9 = $285 +297 = $582

The drama club cannot meet expenses by selling available seats.

where is the triangle?

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3