Can anyone solve this step by step its 3x-2y=5 3x+y=8 in substitution they are both the same problem

3x-2y=5

3x+y=8

Rewrite the second equation as y = -3x +8

Substitute that into the first equation for y:

3x-2(-3x+8) = 5

Use distributive property:

3x +6x -16 = 5

Combine like terms:

9x - 16 = 5

Add 16 to both sides:

9x = 21

Divide both sides by 9:

x = 21/9

x = 7/3

Replace X in the first equation and solve for y:

3(7/3) -2y = 5

7 - 2y = 5

Subtract 7 from both sides:

-2y = -2

Divide both sides by -2:

y = 1

The solution is (7/3, 1)

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.