The length of sally's garden is 4 meters greater than 3 times the width. the perimeter of her garden is 72 meters. find the dimensions of sally's gardens

The length is 28 meters

The width is 8 meters

Step-by-step explanation:

Let x = the length of Sally's garden

Let Y= the width of Sally's garden.

The length of Sally's garden is 4 meters greater than 3 times the width. This means that the length is 3× the width + 4 meters. The equation is

x = 3y + 4

The perimeter of her garden is 72 meters. Since the length and the width are not equal, the garden is a rectangle.

Perimeter of rectangle = 2(length + width). Therefore,

2x + 2y = 72 - - - - - - - - - - -1

Substituting x = 3y + 4 into equation 1, it becomes .

2(3y + 4) + 2y = 72

6y + 8 + 2y = 72

6y + 2y = 72 - 8

8y = 64

y = 64/8 = 8

x = 3y + 4

x = 3×8 + 4 = 24 +4

x = 28

correct answer:

a + bi

452,489 to the nearest thousand is 452,000