Min and max of iid uniforms¶ let ,…,u2,…,un be i. i.d. uniform on (0,1)(0,1) . let )u(1) and (n) be the minimum and maximum of ,…,u2,…,un . a) find the joint density of )u(1) and (n) . b) find the density of )u(1) . c) fix x∈(0,1)x∈(0,1) and find the conditional density of (n) given )=xu(1)=x . d) for fixed x∈(0,1)x∈(0,1) , let ,…−1x1,x2,…,xn−1 be −1n−1 i. i.d. uniform (x,1)(x,1) random variables. find the density of =max{,…−1}m=max{x1,x2,…,xn−1} and compare it to your answer to part c. e) the random variable =−)rn=u(n)−u(1) is called the range of the sample ,…,u2,…,un . find (rn) .

fahrenheit

step-by-step explanation:

fahrenheit is more precise than celsius. the ambient temperature on most of the inhabited world ranges from -20 degrees fahrenheit to 110 degrees fahrenheit—a 130-degree range. on the celsius scale, that range is from -28.8 degrees to 43.3 degrees—a 72.1-degree range. this means that you can get a more exact measurement of the air temperature using fahrenheit because it uses almost twice the scale.

2x^2+5x+17

your welcome. : )

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

his hourly wage would be $8.00/hour.