On a windy day william found that he could travel 10 mi downstream and then 2 mi back
upstream at top speed in a total of 16 min. what was the top speed of william's boat if the rate
of the current was 30 mph? (let x represent the rate of the boat in still water.)

The top speed of William's boat was 45 mph

Step-by-step explanation:

Let

x -----> represent the rate of the boat in still water in mph

we know that

The speed or rate is equal to divide the distance by the time

speed=distance /time

time=distance/speed

Downstream

speed=(30+x) mph

distance=10 mi

time1=10/(30+x)

Upstream

speed=(x-30) mph

distance=2 mi

time2=2/(x-30)

The sum of the time downstream plus the time upstream must be equal to 16 minutes

Convert minutes to hours

Multiply by (x+30)(x-30) both sides

Multiply by 60 both sides

Divide by 16 both sides

The solution is x=45\ mph

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.