In 1990, the mean height of women 20 years of age or older was 63.7 inches based on data obtained from the cdc. suppose that a random sample of 45 women who are 20 years of age or older in 2015 results in a mean height of 63.9 inches with a standard deviation of 0.5 inch. does your sample provide sufficient evidence that women today are taller than in 1990? perform the appropriate test at the 0.05 level of significance

We reject H₀ , we have enough evidence, women today are taller than in 1990

Step-by-step explanation:

The problem is one tail test. We assume height of women follows normal distribution with σ = 0,5 in.

Then    null hypothesis :      H₀    ⇒   μ₀  =  63.7

    Alternative hipothesis:    Hₐ   ⇒    μ   >  63.7

Significance level   0,05       ⇒  z(c)  = 1.645

Statistic z :

z (c)  = ( μ - μ₀ ) / (0,5/√45)    ⇒  z(c)  = (63.9 - 63.7 ) / (0,5 / √45)

z(c) =( 0,2*  √45 ) / 0,5

z(c) =  2,68

Evaluation :  z(s)  > z(c)      2.68 > 1.645

z(c) is in the rejection area  we reject H₀  

47 - 90 = 43

43 - 180 = x

x = 137

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c