Aspherical pressure vessel is required to contain 1.5 m3 of compressed natural gas at 22 mpa . if the tank is made of a516 grade 60 steel with a maximum normal stress 150 mpa , what is the required thickness of the tank wall?

The required thickness of the tank wall is 87.7668 mm.

Step-by-step explanation:

Given :

Volume of vessel is V=1.5 m³.

A spherical pressure vessel is of compressed natural gas at P=22 MPa.

If the tank is made of A516 grade 60 steel with a maximum normal stress 150 MPa.

i.e.

To find : What is the required thickness of the tank wall?

Solution :

The diameter of the vessel is given by,

Convert into mm,

The thickness of the wall tank is given by,

Therefore, the required thickness of the tank wall is 87.7668 mm.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24