1) each week jim buys 10 pounds of macadamia nuts to sell at his store, the nut hut. the number of pounds he actually sells in a week is a continuous random variable y, which has the following probability density function:

fy(y) = y/50 if 0 fy(y) = 0 otherwise

(a) graph this density function.
(b) find the probability that at most four pounds of macadamia nuts are sold.

yes

step-by-step explanation:

i believe the answer is c.

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -