Arock is tossed upward. its height after t seconds is given by s = −16t2 + 24t + 3 feet. what is its maximum height? when does it reach that height?

Step-by-step explanation:

The height of the rock ,(s), in feets after t seconds is given by the function

S = −16t^2 + 24t + 3

The given function is a quadratic equation. If values of height attained is plotted against time, the shape of the graph will be a parabola whose vertex would correspond to the maximum height obtained by the object.

Vertex of the parabola = -b/2a

a = - 16

b = 24

Vertex = - 24/- 16×2 = 24/32

Vertex = 0.75

So the maximum height is 0.75 feet

To determine the time at which it will reach a maximum height of 0.75, we will substitute s = 0.75 into the equation.

S = −16t^2 + 24t + 3

0.75 = −16t^2 + 24t + 3

−16t^2 + 24t + 2.25 = 0

Applying the general formula for quadratic equation,

t = b ± √b^2 - (4ac)]/2a

a = -16

b = 24

c = 2.25

t = - 24 ± √24^2 - 4(-16 × 2.25)]/2×-16

t = - 24 ± √(576  + 144)]/-32

t = - 24 ± √(720)/-32

t = (- 24 ± 26.83)/-32

t = 2.83/-32 or t = -50.83 /-32

t = - 0.088 or t = 1.588

The time cannot be negative so,

The time take to reach maximum height is 1.588 seconds

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft

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step-by-step explanation: