2z+ 1 = z
what value of z satisfies the equation above?

z = -1

Step-by-step explanation:

2z + 1 = z .

To get the value of z that satisfies the equation, what we simply do is to rearrange the equation by moving the coefficients. Now, we move z to the left hand side of the equation and 1 to the right side of the equation.

We should note that their signs will change afterwards.

2z - z = -1

z = -1

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

answer

106 emergencies

step-by-step explanation: