If the length of the rectangle is twice the width, and the perimeter of the rectangle is 30m, what is length and width of the rectangle

The length of the rectangle=10 m

The width of the rectangle=5 m

Step-by-step explanation:

Step 1: Determine the dimensions of the rectangle

let the width of the rectangle be;

width=w

length=2×w=2 w

Step 2: Determine the perimeter of the rectangle

P=2(L+W)

where;

P=perimeter of the rectangle

L=length of the rectangle

W=width of the rectangle

In our case;

P=30 m

L=2 w

W=w

replacing;

2(2 w+w)=30

4 w+2 w=30

6 w=30

w=30/6=5

w=5 m

The length of the rectangle=5×2=10 m

The width of the rectangle=5 m

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

answer: i believe the answer is e

step-by-step explanation: