Atire manufacturer estimates that their tires last, an average of 40,000 miles, with a standard deviation of 5000. what is the probability that a randomly chosen tire from this manufacturer lasts between 30,000 miles and 50,000 miles? (give your answer as a decimal rounded to 4 decimal places.) check reference 2. the daily high temperature on october 31 in a certain city is normally distributed with 50 and 0 8. what is the probability that the high temperature on october 31 in a randomly chosen year will be between 46 degrees and 58 degrees? (give your answer as a decimal rounded to 4 decimal places.)

0.9554,0.8188

Step-by-step explanation:

Given that a tire manufacturer estimates that their tires last, an average of 40,000 miles, with a standard deviation of 5000.

X - duration of tires is N(40000,5000)

Or Z = is N(0,1)

the probability that a randomly chosen tire from this manufacturer lasts between 30,000 miles and 50,000 miles

=

------------------------------------

2) Given that the daily high temperature on October 31 in a certain city is normally distributed with 50 and 8

Y - daily high temp on Oct 31 is N(50,8)

Or Z = is N(0,1)

the probability that a randomly chosen tire from this manufacturer lasts between 46 degrees and 58 degrees

=

answer: 25.4 units

step-by-step explanation: radius = 12.7 units

diameter = twice the radius

diameter = 12.7 x 2

= 25.4

answer: finding the extract measurements and knowing the points

step-by-step explanation: