Asample of 31 boxes of cereal has a sample standard deviation of 0.81 ounces. construct a 93% confidence interval to estimate the true standard deviation of the fllins process for the boxes of cereal. a (0433, 1.120) b)(0.658,1.058) c (0.525, 1095) d (0.731,0.731) e) none of the above.

 Option 'b' is correct.

Step-by-step explanation:

Since we have given that

s = 0.81

n = 31

We need to find the 93% confidence interval to estimate the true standard deviation.

degrees of freedom = df = n-1=30

Here, α = 0.93

1-α=0.07

so,

and

So, we will use "Chi square distribution"

So, the interval would be

Hence, 93% confidence interval would be (0.6581,1.058).

Therefore, Option 'b' is correct.

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step-by-step explanation: