Math is due today! 100 points and brainliest to the right !

a triangle has vertices a (2, -2), b (-2, 5), and c (-4, 2).
hint: see lesson 4.06 and page 93, 94, and 97.

1.)the slope of line segment ab is units.

2.)the slope of line segment bc is units.

3.)the slope of line segment ac is units.

4.)by looking at these slopes, you can tell that triangle abc is a right triangle, because

=

answer:

1.)the slope of line segment ab is -7/4 units.

2.)the slope of line segment bc is 3/2 units.

3.)the slope of line segment ac is -2/3 units.

4.)by looking at these slopes, you can tell that triangle abc is a right triangle, because

(3//3) = (-1).

step-by-step explanation:

a (2, -2), b (-2, 5), and c (-4, 2)

slope is

m = (y2-y1)/(x2-x1)

slope of ab

a (2, -2) and b (-2, 5)

m = (y2-y1)/(x2-x1)

m = (7)/(-4)

m = -7/4

slope of bc

b (-2, 5) and c (-4, 2)

m = (y2-y1)/(x2-x1)

m = (-3)/(-2))

m = 3/2

slope of ac

a (2, -2) and c (-4, 2)

m = (y2-y1)/(x2-x1)

m = ())/(-4-2)

m = (4)/(-6)

m = -4/6

m = -2/3

perpendicular slopes

since there are two of these slopes that are negative reciprocals of each other, there is a pair of perpendicular lines, meaning a 90 degree angle, a right triangle.

the negative reciprocal slopes, when multiplied, produce -1.

-2/3 and 3/2 are negative reciprocals because they have different signs, one is negative and the other is positive. their top and bottom numbers are switched.

if you use photomath right away it will give you the answer not like this app that you have to wait for people.

a - base

b - exponent

so,