Solutions of aluminum nitrate and sodium sulfate react to form sodium nitrate and aluminum sulfate. balance this reaction.

_al(no3)3(aq)+__na2so4(aq) —> al2(so4)3(s) + nano3(aq)

1,3,1,6
2,3,1,6
2,3,1,3
3,3,2,6

2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → 1Al₂(SO₄)₃(s) + 6NaNO₃(aq)

2, 3, 1, 6

Second choice.

Step-by-step explanation:

Count the number of atoms on each side. Keep polyatomic ions together because they exist on both sides. After each coefficient you write in, recount the number of atoms.

Al(NO₃)₃(aq) + Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)

Al         1                                  Al         2

NO₃     3                                 NO₃      1

Na        2                                 Na        1

SO₄      1                                 SO₄      3

Balance the sulfates (SO₄) by multiplying it by 3 on the left. Sodium (Na) will also change.

Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)

Al         1                                  Al         2

NO₃     3                                 NO₃      1

Na        6                                 Na        1

SO₄      3                                 SO₄      3

Balance sodium (Na) by multiplying it on the left by 6. Nitrate (NO₃) will also change.

Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)

Al         1                                  Al         2

NO₃     3                                 NO₃      6

Na        6                                 Na        6

SO₄      3                                 SO₄      3

Balance the number of nitrates (NO₃) on the left. Multiply by 2. Aluminum (Al) also changes.

2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)

Al         2                                  Al         2

NO₃     6                                 NO₃      6

Na        6                                 Na        6

SO₄      3                                 SO₄      3

The same number of each atom is on each side, so the equation is balanced.

If there is no coefficient, treat it as 1.

2,3,1,6

i dont know sorry

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497